1. Consider a 200 mL solution at room temperature, containing an unknown amount of cadmium ions. Using a cadmium ion selective electrode, with a half cell potential given by the Nernst equation E= E° + (RT/nF)ln[Cd2+], and a calomel standard electrode, the potential of the cell was found to be -0.72 V. To this solution, 30 mL of 5 mM CdCl2 was added and the potential of the cell changed to -0.65 V.
a) What was the initial concentration of cadmium ions?
b) Assuming an uncertainty of +0.5 mV in the measurements of the potential, what is the error in the answer? Get Chemistry help Today
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